实现手写JSON解析的方法需要深入理解JSON的语法规则,并能够解析JSON字符串,提取其中的键值对和嵌套的JSON对象。以下是一个简单的C语言实现手写JSON解析的示例代码:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
// 定义JSON对象结构体
typedef struct json_object {
char *key;
char *value;
struct json_object *next;
} json_object;
// 定义JSON数组结构体
typedef struct json_array {
json_object *objects;
int length;
} json_array;
// 解析JSON字符串,返回JSON对象链表
json_object *parse_json(char *json) {
json_object *root = NULL;
json_object *object = NULL;
char *key = NULL;
char *value = NULL;
int depth = 0;
int i = 0;
while (json[i] != '\0') {
if (json[i] == '}') {
depth--;
if (depth == 0) {
if (root == NULL) {
root = object;
} else {
json_object *temp = root;
while (temp->next != NULL) {
temp = temp->next;
}
temp->next = object;
}
object = NULL;
}
} else if (json[i] == '{') {
depth++;
object = (json_object*)malloc(sizeof(json_object));
object->key = NULL;
object->value = NULL;
object->next = NULL;
} else if (json[i] == '\"') {
int j = i + 1;
while (1) {
if (json[j] == '\\') {
j++;
} else if (json[j] == '\"') {
break;
} else {
j++;
}
}
value = (char*)malloc(j - i - 1);
strncpy(value, json + i + 1, j - i - 2);
value[j - i - 2] = '\0';
} else if (json[i] == ':') {
key = value;
value = NULL;
} else if (json[i] == ',') {
if (key != NULL && object != NULL) {
object->key = key;
object->value = value;
object->next = (json_object*)malloc(sizeof(json_object));
object = object->next;
object->key = NULL;
object->value = NULL;
} else {
break;
}
} else if (depth == 0 && json[i] != ' ') {
value = (char*)malloc(strlen("null") + 1);
strcpy(value, "null");
} else if (depth == 1 && json[i] != ' ') {
break;
} else {
i++;
}
i++;
}
return root;
}